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Find the Exact Value Under the Given Conditions $\cos \alpha = \frac { 1 } { 3 } , 0 < \alpha < \frac { \pi } { 2 } ; \quad \sin \beta = - \frac { 1 } { 2 } , - \frac { \pi } { 2 } < \beta < 0$

Question 193

Multiple Choice

Find the exact value under the given conditions.
- $\cos \alpha = \frac { 1 } { 3 } , 0 < \alpha < \frac { \pi } { 2 } ; \quad \sin \beta = - \frac { 1 } { 2 } , - \frac { \pi } { 2 } < \beta < 0$
Find $\tan ( \alpha + \beta )$

A) $\frac { 9 \sqrt { 3 } + 8 \sqrt { 2 } } { 3 }$

B) $\frac { 9 \sqrt { 3 } + 8 \sqrt { 2 } } { 5 }$

C) $\frac { 9 \sqrt { 3 } - 8 \sqrt { 2 } } { 5 }$

D) $\frac { 9 \sqrt { 3 } - 8 \sqrt { 2 } } { 3 }$

Find the Exact Value Under the Given Conditions cos⁡α=13,0<α<π2;sin⁡β=−12,−π2<β<0\cos \alpha = \frac { 1 } { 3 } , 0 < \alpha < \frac { \pi } { 2 } ; \quad \sin \beta = - \frac { 1 } { 2 } , - \frac { \pi } { 2 } < \beta < 0cosα=31​,0<α<2π​;sinβ=−21​,−2π​<β<0

Multiple Choice

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Find the Exact Value Under the Given Conditions $\cos \alpha = \frac { 1 } { 3 } , 0 < \alpha < \frac { \pi } { 2 } ; \quad \sin \beta = - \frac { 1 } { 2 } , - \frac { \pi } { 2 } < \beta < 0$

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