Solve the Problem $M = 750 + 125 \sin \frac { \pi } { 6 } t$

Solve the problem.
-Wildlife management personnel use predator-prey equations to model the populations of certain predators and
their prey in the wild. Suppose the population M of a predator after t months is given by $M = 750 + 125 \sin \frac { \pi } { 6 } t$ while the population N of its primary prey is given by $N = 12,250 + 3050 \cos \frac { \pi } { 6 } t$ Find the values of t $0 \leq t < 12$ or which the predator population is 875. Find the values of t, $0 \leq t < 12$ for which
the prey population is 10,725.

Correct Answer:

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M = 875, t...

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