Solve the Problem $$P = 4 \cos ( 4 t )$$

Solve the problem.
-A mass hangs from a spring which oscillates up and down. The position P (in feet) of the mass at time t (in seconds) is
given by $$P = 4 \cos ( 4 t )$$
For what values of $t , 0 \leq t < \pi$ , will the position be $2 \sqrt { 2 }$ feet? Find the exact values. Do not use a calculator.

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