Solved

Discuss the Equation and Graph It $r = \frac { 3 } { 2 + 4 \sin \theta }$

Question 55

Multiple Choice

Discuss the equation and graph it.
- $r = \frac { 3 } { 2 + 4 \sin \theta }$
$Discuss the equation and graph it. - r = \frac { 3 } { 2 + 4 \sin \theta } A) ellipse, directrix parallel to the polar axis \frac{3}{2} unit below the pole vertices \left(\frac{3}{2}, \frac{\pi}{2}\right) ,\left(\frac{1}{2}, \frac{3 \pi}{2}\right) B) ellipse, directrix perpendicular to the polar axis \frac{3}{2} unit left of the pole vertices \left(\frac{3}{2}, 0\right) ,\left(\frac{1}{2}, \pi\right) C) hyperbola; directrix parallel to the polar axis \frac{3}{4} unit above the pole vertices \left(\frac{1}{2}, \frac{\pi}{2}\right) ,\left(-\frac{3}{2}, \frac{3 \pi}{2}\right) D) hyperbola, directrix perpendicular to the polar axis \frac{3}{4} unit right of the pole vertices \left(\frac{1}{2}, 0\right) ,\left(-\frac{3}{2}, \pi\right)$

A) ellipse, directrix parallel to the polar axis $\frac{3}{2}$ unit below the pole vertices $\left(\frac{3}{2}, \frac{\pi}{2}\right) ,\left(\frac{1}{2}, \frac{3 \pi}{2}\right)$
$Discuss the equation and graph it. - r = \frac { 3 } { 2 + 4 \sin \theta } A) ellipse, directrix parallel to the polar axis \frac{3}{2} unit below the pole vertices \left(\frac{3}{2}, \frac{\pi}{2}\right) ,\left(\frac{1}{2}, \frac{3 \pi}{2}\right) B) ellipse, directrix perpendicular to the polar axis \frac{3}{2} unit left of the pole vertices \left(\frac{3}{2}, 0\right) ,\left(\frac{1}{2}, \pi\right) C) hyperbola; directrix parallel to the polar axis \frac{3}{4} unit above the pole vertices \left(\frac{1}{2}, \frac{\pi}{2}\right) ,\left(-\frac{3}{2}, \frac{3 \pi}{2}\right) D) hyperbola, directrix perpendicular to the polar axis \frac{3}{4} unit right of the pole vertices \left(\frac{1}{2}, 0\right) ,\left(-\frac{3}{2}, \pi\right)$

B) ellipse, directrix perpendicular to the polar axis $\frac{3}{2}$ unit left of the pole vertices $\left(\frac{3}{2}, 0\right) ,\left(\frac{1}{2}, \pi\right)$
$Discuss the equation and graph it. - r = \frac { 3 } { 2 + 4 \sin \theta } A) ellipse, directrix parallel to the polar axis \frac{3}{2} unit below the pole vertices \left(\frac{3}{2}, \frac{\pi}{2}\right) ,\left(\frac{1}{2}, \frac{3 \pi}{2}\right) B) ellipse, directrix perpendicular to the polar axis \frac{3}{2} unit left of the pole vertices \left(\frac{3}{2}, 0\right) ,\left(\frac{1}{2}, \pi\right) C) hyperbola; directrix parallel to the polar axis \frac{3}{4} unit above the pole vertices \left(\frac{1}{2}, \frac{\pi}{2}\right) ,\left(-\frac{3}{2}, \frac{3 \pi}{2}\right) D) hyperbola, directrix perpendicular to the polar axis \frac{3}{4} unit right of the pole vertices \left(\frac{1}{2}, 0\right) ,\left(-\frac{3}{2}, \pi\right)$

C) hyperbola; directrix parallel to the polar axis $\frac{3}{4}$ unit above the pole vertices $\left(\frac{1}{2}, \frac{\pi}{2}\right) ,\left(-\frac{3}{2}, \frac{3 \pi}{2}\right)$
$Discuss the equation and graph it. - r = \frac { 3 } { 2 + 4 \sin \theta } A) ellipse, directrix parallel to the polar axis \frac{3}{2} unit below the pole vertices \left(\frac{3}{2}, \frac{\pi}{2}\right) ,\left(\frac{1}{2}, \frac{3 \pi}{2}\right) B) ellipse, directrix perpendicular to the polar axis \frac{3}{2} unit left of the pole vertices \left(\frac{3}{2}, 0\right) ,\left(\frac{1}{2}, \pi\right) C) hyperbola; directrix parallel to the polar axis \frac{3}{4} unit above the pole vertices \left(\frac{1}{2}, \frac{\pi}{2}\right) ,\left(-\frac{3}{2}, \frac{3 \pi}{2}\right) D) hyperbola, directrix perpendicular to the polar axis \frac{3}{4} unit right of the pole vertices \left(\frac{1}{2}, 0\right) ,\left(-\frac{3}{2}, \pi\right)$

D) hyperbola, directrix perpendicular to the polar axis $\frac{3}{4}$ unit right of the pole vertices $\left(\frac{1}{2}, 0\right) ,\left(-\frac{3}{2}, \pi\right)$
$Discuss the equation and graph it. - r = \frac { 3 } { 2 + 4 \sin \theta } A) ellipse, directrix parallel to the polar axis \frac{3}{2} unit below the pole vertices \left(\frac{3}{2}, \frac{\pi}{2}\right) ,\left(\frac{1}{2}, \frac{3 \pi}{2}\right) B) ellipse, directrix perpendicular to the polar axis \frac{3}{2} unit left of the pole vertices \left(\frac{3}{2}, 0\right) ,\left(\frac{1}{2}, \pi\right) C) hyperbola; directrix parallel to the polar axis \frac{3}{4} unit above the pole vertices \left(\frac{1}{2}, \frac{\pi}{2}\right) ,\left(-\frac{3}{2}, \frac{3 \pi}{2}\right) D) hyperbola, directrix perpendicular to the polar axis \frac{3}{4} unit right of the pole vertices \left(\frac{1}{2}, 0\right) ,\left(-\frac{3}{2}, \pi\right)$

Discuss the Equation and Graph It r=32+4sin⁡θr = \frac { 3 } { 2 + 4 \sin \theta }r=2+4sinθ3​

Multiple Choice

Correct Answer:VerifiedUnlock this answer nowGet Access to more Verified Answers free of chargeAccess For Free

Discuss the Equation and Graph It $r = \frac { 3 } { 2 + 4 \sin \theta }$

Correct Answer:
Verified
Unlock this answer now
Get Access to more Verified Answers free of charge