Solve the Problem $1.7556 \times 10 ^ { 5 }$ Three-Number "Combinations"
C)

Solve the problem.
-How many different three-number "combinations" are possible on a combination lock having 22 numbers on its dial? Assume that no numbers repeat. (Combination locks are really permutation
Locks.)

A) 9240 three-number "combinations"
B) $1.7556 \times 10 ^ { 5 }$ three-number "combinations"
C) $1.0534 \times 10 ^ { 6 }$ three-number "combinations"
D) $3.5112 \times 10 ^ { 5 }$ three-number "combinations"

Correct Answer:

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