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Decide What Values of the Variable Cannot Possibly Be Solutions $6 x ^ { - 2 } - 31 x ^ { - 1 } + 5 = 0$

Question 12

Multiple Choice

Decide what values of the variable cannot possibly be solutions for the equation.
- $6 x ^ { - 2 } - 31 x ^ { - 1 } + 5 = 0$

A) $\left\{ - \frac { 1 } { 6 } , - 5 \right\}$
B) $\left\{ \frac { 1 } { 6 } , 5 \right\}$
C) $\left\{ 6 , \frac { 1 } { 5 } \right\}$
D) $\left\{ - 6 , - \frac { 1 } { 5 } \right\}$

Decide What Values of the Variable Cannot Possibly Be Solutions 6x−2−31x−1+5=06 x ^ { - 2 } - 31 x ^ { - 1 } + 5 = 06x−2−31x−1+5=0

Multiple Choice

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Decide What Values of the Variable Cannot Possibly Be Solutions $6 x ^ { - 2 } - 31 x ^ { - 1 } + 5 = 0$

Correct Answer:
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