Decide What Values of the Variable Cannot Possibly Be Solutions $\sqrt [ 3 ] { 4 + 6 x } - \sqrt [ 3 ] { 1 - 8 x } = 0$

Decide what values of the variable cannot possibly be solutions for the equation.
- $\sqrt [ 3 ] { 4 + 6 x } - \sqrt [ 3 ] { 1 - 8 x } = 0$

A) $\left\{ \frac { 14 } { 3 } \right\}$
B) $\left\{ - \frac { 3 } { 14 } \right\}$
C) $\left\{ \frac { 3 } { 14 } \right\}$
D) $\left\{ - \frac { 14 } { 3 } \right\}$

Correct Answer:

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