Decide What Values of the Variable Cannot Possibly Be Solutions $$\frac { 3 } { x + 5 } + \frac { 8 } { x + 2 } = \frac { 10 } { x ^ { 2 } + 7 x + 10 }$$

Decide what values of the variable cannot possibly be solutions for the equation.
- $$\frac { 3 } { x + 5 } + \frac { 8 } { x + 2 } = \frac { 10 } { x ^ { 2 } + 7 x + 10 }$$

A) $\varnothing$
B) $\left\{ - \frac { 39 } { 7 } \right\}$
C) $\left\{ - \frac { 36 } { 11 } \right\}$
D) $\left\{ - \frac { 56 } { 11 } \right\}$

Correct Answer:

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Access For Free