Give a Rule for the Piecewise-Defined Function f(x)={x3x+4 if x<1 if x≥1;
Question 262
Question 262
Multiple Choice
Give a rule for the piecewise-defined function. Then give the domain and range. -
A) f(x) ={x3x+4 if x<1 if x≥1; Domain: (∞,∞) , Range: (∞,1) ∪[5,∞) B) f(x) ={x3x−4 if x<1 if x≥1; Domain: (∞,1) ∪[5,∞) , Range: (∞,∞) C) f(x) ={3xx+4 if x<1; Domain: (∞,∞) , Range: (∞,1) ∪[5,∞) if x≥1 D) f(x) ={−x3x−4 if x<1 if x≥1; Domain: (∞,1) ∪[5,∞) , Range: (∞,∞)
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![Give a rule for the piecewise-defined function. Then give the domain and range. - A) f ( x ) = \left\{ \begin{array} { l l } x ^ { 3 } & \text { if } x < 1 \\ x + 4 & \text { if } x \geq 1 \end{array} ; \right. Domain: ( \infty , \infty ) , Range: ( \infty , 1 ) \cup [ 5 , \infty ) B) f ( x ) = \left\{ \begin{array} { l l } x ^ { 3 } & \text { if } x < 1 \\ x - 4 & \text { if } x \geq 1 \end{array} ; \right. Domain: ( \infty , 1 ) \cup [ 5 , \infty ) , Range: ( \infty , \infty ) C) f ( x ) = \left\{ \begin{array} { l l } \sqrt [ 3 ] { x } & \text { if } x < 1 ; \text { Domain: } ( \infty , \infty ) , \text { Range: } ( \infty , 1 ) \cup [ 5 , \infty ) \\ x + 4 & \text { if } x \geq 1 \end{array} \right. D) f ( x ) = \left\{ \begin{array} { l l } - x ^ { 3 } & \text { if } x < 1 \\ x - 4 & \text { if } x \geq 1 \end{array} ; \right. Domain: ( \infty , 1 ) \cup [ 5 , \infty ) , Range: ( \infty , \infty )](https://d2lvgg3v3hfg70.cloudfront.net/TB7516/11ecc542_b08d_5b1e_8347_3b0ff7396278_TB7516_11.jpg)
