A Coin Is Tossed Upward from a Balcony 200 Feet $h ( t ) = - 16 t ^ { 2 } + 48 t + 200$

A coin is tossed upward from a balcony 200 feet high with an initial velocity of 48 feet per second, then its height after t seconds is given by the equation $h ( t ) = - 16 t ^ { 2 } + 48 t + 200$
During what interval of time will the coin be at a height of at least 40 ft?

A) $0 \leq t \leq 5$
B) $4 \leq t \leq 5$
C) $0 \leq t \leq 1$
D) $5 \leq t \leq 10$

Correct Answer:

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