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Solve the System $\begin{array} { r } 4 x - 2 y - 3 z + 1 = 0 \\12 x - 2 y + 6 z - 4 = 0 \\4 y + 3 z - 3 = 0\end{array}$

Question 446

Multiple Choice

Solve the system.
$\begin{array} { r } 4 x - 2 y - 3 z + 1 = 0 \\12 x - 2 y + 6 z - 4 = 0 \\4 y + 3 z - 3 = 0\end{array}$

A) $\left\{ \left( - \frac { 1 } { 4 } , \frac { 1 } { 2 } , - \frac { 1 } { 3 } \right) \right\}$
B) $\left\{ \left( \frac { 1 } { 4 } , \frac { 1 } { 2 } , \frac { 1 } { 3 } \right) \right\}$
C) $\varnothing$

D) $\left\{ \left( - \frac { 1 } { 4 } , - \frac { 1 } { 2 } , \frac { 1 } { 3 } \right) \right\}$

Solve the System 4x−2y−3z+1=012x−2y+6z−4=04y+3z−3=0\begin{array} { r } 4 x - 2 y - 3 z + 1 = 0 \\12 x - 2 y + 6 z - 4 = 0 \\4 y + 3 z - 3 = 0\end{array}4x−2y−3z+1=012x−2y+6z−4=04y+3z−3=0​

Multiple Choice

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Solve the System $\begin{array} { r } 4 x - 2 y - 3 z + 1 = 0 \\12 x - 2 y + 6 z - 4 = 0 \\4 y + 3 z - 3 = 0\end{array}$

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