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Solve the System by Elimination x+45+2y−x10=2x+24+3y+45=−3\begin{array} { l } \frac { x + 4 } { 5 } + \frac { 2 y - x } { 10 } = 2 \\\frac { x + 2 } { 4 } + \frac { 3 y + 4 } { 5 } = - 3\end{array}

Question 181

Multiple Choice

Solve the system by elimination.
x+45+2y−x10=2x+24+3y+45=−3\begin{array} { l } \frac { x + 4 } { 5 } + \frac { 2 y - x } { 10 } = 2 \\\frac { x + 2 } { 4 } + \frac { 3 y + 4 } { 5 } = - 3\end{array}


A) {(158,−73) }\{ ( 158 , - 73 ) \}
B) ϕ\phi
C) {(−14,13) }\{ ( - 14,13 ) \}
D) {(−73,158) }\{ ( - 73,158 ) \}

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