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To Graph x216−y236=1\frac { x ^ { 2 } } { 16 } - \frac { y ^ { 2 } } { 36 } = 1

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To graph x216−y236=1\frac { x ^ { 2 } } { 16 } - \frac { y ^ { 2 } } { 36 } = 1 on a graphics calculator, we must consider the union of the graphs of the two functions, y1=6x216−1y _ { 1 } = 6 \sqrt { \frac { x ^ { 2 } } { 16 } - 1 } and y2=−6x216−1y _ { 2 } = - 6 \sqrt { \frac { x ^ { 2 } } { 16 } - 1 } . Using the graph of y=x216−1y = \frac { x ^ { 2 } } { 16 } - 1 , explain (a) how the solution set of x216−1≥0\frac { x ^ { 2 } } { 16 } - 1 \geq 0 can be determined graphically and (b) how it relates to the domain of the hyperbola.
 To graph  \frac { x ^ { 2 } } { 16 } - \frac { y ^ { 2 } } { 36 } = 1  on a graphics calculator, we must consider the union of the graphs of the two functions,  y _ { 1 } = 6 \sqrt { \frac { x ^ { 2 } } { 16 } - 1 }  and  y _ { 2 } = - 6 \sqrt { \frac { x ^ { 2 } } { 16 } - 1 } . Using the graph of  y = \frac { x ^ { 2 } } { 16 } - 1 , explain (a) how the solution set of  \frac { x ^ { 2 } } { 16 } - 1 \geq 0  can be determined graphically and (b) how it relates to the domain of the hyperbola.

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