Solve the Problem $x = - 3$ At $( - 3,5 )$

Solve the problem.
-Find the equation of a circle in standard form that is tangent to the line $x = - 3$ at $( - 3,5 )$ and also tangent to the line $x = 9$ .

A) $( x - 3 ) ^ { 2 } + ( y + 5 ) ^ { 2 } = 36$
B) $( x + 3 ) ^ { 2 } + ( y + 5 ) ^ { 2 } = 36$
C) $( x + 3 ) ^ { 2 } + ( y - 5 ) ^ { 2 } = 36$
D) $( x - 3 ) ^ { 2 } + ( y - 5 ) ^ { 2 } = 36$

Correct Answer:

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