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Solve the Problem y=(tan⁡θ)x−16v2cos⁡2θx2y = ( \tan \theta ) x - \frac { 16 } { v ^ { 2 } \cos ^ { 2 } \theta } x ^ { 2 }

Question 321

Multiple Choice

Solve the problem.
-The altitude of a projectile in feet (neglecting air resistance) is given by
y=(tan⁡θ) x−16v2cos⁡2θx2y = ( \tan \theta ) x - \frac { 16 } { v ^ { 2 } \cos ^ { 2 } \theta } x ^ { 2 }
where xx is the horizontal distance covered in feet and vv is the initial velocity of the projectile at an angle θ\theta from tt ] horizontal. Find the firing angle (in degrees) of a projectile fired at an initial velocity of 100 feet per second so that it strikes the ground 312.5312.5 feet from the firing point.


A) 30∘30 ^ { \circ }
B) 45∘45 ^ { \circ }
C) 50∘50 ^ { \circ }
D) 22.5∘22.5 ^ { \circ }

Correct Answer:

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