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Transform the Polar Equation to an Equation in Rectangular Coordinates $r \sec \theta = - 6$

Question 151

Multiple Choice

Transform the polar equation to an equation in rectangular coordinates. Then identify and graph the equation.
- $r \sec \theta = - 6$
$Transform the polar equation to an equation in rectangular coordinates. Then identify and graph the equation. - r \sec \theta = - 6 A) B) (x+3) ^{2}+y^{2}=9 ; circle, radius 3 center (-3,0) in rectangular coordinates C) y=-6 ; horizontal line 6 units below the pole D) x=-6 ; vertical line 6 units to the left of the pole x^{2}+(y+3) ^{2}=9 ; circle, radius 3 , center at (0,-3) in rectangular coordinates$

A)
$Transform the polar equation to an equation in rectangular coordinates. Then identify and graph the equation. - r \sec \theta = - 6 A) B) (x+3) ^{2}+y^{2}=9 ; circle, radius 3 center (-3,0) in rectangular coordinates C) y=-6 ; horizontal line 6 units below the pole D) x=-6 ; vertical line 6 units to the left of the pole x^{2}+(y+3) ^{2}=9 ; circle, radius 3 , center at (0,-3) in rectangular coordinates$

B)
$Transform the polar equation to an equation in rectangular coordinates. Then identify and graph the equation. - r \sec \theta = - 6 A) B) (x+3) ^{2}+y^{2}=9 ; circle, radius 3 center (-3,0) in rectangular coordinates C) y=-6 ; horizontal line 6 units below the pole D) x=-6 ; vertical line 6 units to the left of the pole x^{2}+(y+3) ^{2}=9 ; circle, radius 3 , center at (0,-3) in rectangular coordinates$
$(x+3) ^{2}+y^{2}=9 ;$ circle, radius 3
center $(-3,0)$ in rectangular coordinates

C)
$Transform the polar equation to an equation in rectangular coordinates. Then identify and graph the equation. - r \sec \theta = - 6 A) B) (x+3) ^{2}+y^{2}=9 ; circle, radius 3 center (-3,0) in rectangular coordinates C) y=-6 ; horizontal line 6 units below the pole D) x=-6 ; vertical line 6 units to the left of the pole x^{2}+(y+3) ^{2}=9 ; circle, radius 3 , center at (0,-3) in rectangular coordinates$

$y=-6$ ; horizontal line 6 units below the pole
D)
$Transform the polar equation to an equation in rectangular coordinates. Then identify and graph the equation. - r \sec \theta = - 6 A) B) (x+3) ^{2}+y^{2}=9 ; circle, radius 3 center (-3,0) in rectangular coordinates C) y=-6 ; horizontal line 6 units below the pole D) x=-6 ; vertical line 6 units to the left of the pole x^{2}+(y+3) ^{2}=9 ; circle, radius 3 , center at (0,-3) in rectangular coordinates$

$x=-6$ ; vertical line 6 units to the left of the pole

$x^{2}+(y+3) ^{2}=9 ;$ circle, radius 3 ,
center at $(0,-3)$ in rectangular coordinates

Transform the Polar Equation to an Equation in Rectangular Coordinates rsec⁡θ=−6r \sec \theta = - 6rsecθ=−6

Multiple Choice

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Transform the Polar Equation to an Equation in Rectangular Coordinates $r \sec \theta = - 6$

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