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Find the Center, Transverse Axis, Vertices, Foci, and Asymptotes of the Hyperbola

Question 151

Multiple Choice

Find the center, transverse axis, vertices, foci, and asymptotes of the hyperbola.
- (x−3) 2−9(y+3) 2=9( x - 3 ) ^ { 2 } - 9 ( y + 3 ) ^ { 2 } = 9


A) center at (3,−3) ( 3 , - 3 )
transverse axis is parallel to y\mathrm { y } -axis
vertices at (3,−6) ( 3 , - 6 ) and (3,0) ( 3,0 ) ,
foci at (3,−3−10) ( 3 , - 3 - \sqrt { 10 } ) and (3,−3+10) ( 3 , - 3 + \sqrt { 10 } ) ,
asymptotes of y−3=−3(x+3) y - 3 = - 3 ( x + 3 ) and y−3=3(x+3) y - 3 = 3 ( x + 3 )

B) center at (3,−3) ( 3 , - 3 )
transverse axis is parallel to xx -axis
vertices at (0,−3) ( 0 , - 3 ) and (6,−3) ( 6 , - 3 )
foci at (3−10,−3) ( 3 - \sqrt { 10 } , - 3 ) and (3+10,−3) ( 3 + \sqrt { 10 } , - 3 )
asymptotes of y+3=−13(x−3) y + 3 = - \frac { 1 } { 3 } ( x - 3 ) and y+3=13(x−3) y + 3 = \frac { 1 } { 3 } ( x - 3 )

C) center at (−3,3) ( - 3,3 )
transverse axis is parallel to xx -axis
vertices at (−6,3) ( - 6,3 ) and (0,3) ( 0,3 )
foci at (−3−10,3) ( - 3 - \sqrt { 10 } , 3 ) and (−3+10,3) ( - 3 + \sqrt { 10 } , 3 )
asymptotes of y−3=−13(x+3) y - 3 = - \frac { 1 } { 3 } ( x + 3 ) and y−3=13(x+3) y - 3 = \frac { 1 } { 3 } ( x + 3 )

D) center at (3,−3) ( 3 , - 3 )
transverse axis is parallel to xx -axis
vertices at (2,−3) ( 2 , - 3 ) and (4,−3) ( 4 , - 3 )
foci at (3−10,−3) ( 3 - \sqrt { 10 } , - 3 ) and (3+10,−3) ( 3 + \sqrt { 10 } , - 3 )
asymptotes of y+3=−3(x−3) y + 3 = - 3 ( x - 3 ) and y+3=3(x−3) y + 3 = 3 ( x - 3 )

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