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Decide What Values of the Variable Cannot Possibly Be Solutions 3x−2+18x−1+15=03 x ^ { - 2 } + 18 x ^ { - 1 } + 15 = 0

Question 413

Multiple Choice

Decide what values of the variable cannot possibly be solutions for the equation.
- 3x−2+18x−1+15=03 x ^ { - 2 } + 18 x ^ { - 1 } + 15 = 0


A) {−1,−5}\{ - 1 , - 5 \}
B) {1,5}\{ 1,5 \}
C) {−1,−15}\left\{ - 1 , - \frac { 1 } { 5 } \right\}
D) {1,15}\left\{ 1 , \frac { 1 } { 5 } \right\}

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