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Decide What Values of the Variable Cannot Possibly Be Solutions (x+3)4−5(x+3)2+4=0( x + 3 ) ^ { 4 } - 5 ( x + 3 ) ^ { 2 } + 4 = 0

Question 247

Multiple Choice

Decide what values of the variable cannot possibly be solutions for the equation.
- (x+3) 4−5(x+3) 2+4=0( x + 3 ) ^ { 4 } - 5 ( x + 3 ) ^ { 2 } + 4 = 0


A) {1,4}\{ 1,4 \}
B) {−1,−4}\{ - 1 , - 4 \}
C) {−2,−1,1,2}\{ - 2 , - 1,1,2 \}
D) {−5,−4,−2,−1}\{ - 5 , - 4 , - 2 , - 1 \}

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