Decide What Values of the Variable Cannot Possibly Be Solutions$$\left( x ^ { 2 } - 3 \right) ^ { 1 / 2 } - ( x + 3 ) ^ { 1 / 2 } = 0$$

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The Answer of Decide What Values of the Variable Cannot Possibly Be Solutions$$\left( x ^ { 2 } - 3 \right) ^ { 1 / 2 } - ( x + 3 ) ^ { 1 / 2 } = 0$$

Decide What Values of the Variable Cannot Possibly Be Solutions $\left( x ^ { 2 } - 3 \right) ^ { 1 / 2 } - ( x + 3 ) ^ { 1 / 2 } = 0$