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Decide What Values of the Variable Cannot Possibly Be Solutions 1+1x=6x21 + \frac { 1 } { x } = \frac { 6 } { x ^ { 2 } }

Question 345

Multiple Choice

Decide what values of the variable cannot possibly be solutions for the equation.
- 1+1x=6x21 + \frac { 1 } { x } = \frac { 6 } { x ^ { 2 } }


A) {−3,2}\{ - 3,2 \}
B) {−13,12}\left\{ - \frac { 1 } { 3 } , \frac { 1 } { 2 } \right\}
C) {2,3}\{ 2,3 \}
D) {−2,3}\{ - 2,3 \}

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