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Decide What Values of the Variable Cannot Possibly Be Solutions 5x−5+14x−8=16x2−13x+40\frac { 5 } { x - 5 } + \frac { 14 } { x - 8 } = \frac { 16 } { x ^ { 2 } - 13 x + 40 }

Question 435

Multiple Choice

Decide what values of the variable cannot possibly be solutions for the equation.
- 5x−5+14x−8=16x2−13x+40\frac { 5 } { x - 5 } + \frac { 14 } { x - 8 } = \frac { 16 } { x ^ { 2 } - 13 x + 40 }


A) ∅\varnothing

B) {12619}\left\{ \frac { 126 } { 19 } \right\}

C) {9419}\left\{ \frac { 94 } { 19 } \right\}


D) {−3313}\left\{ - \frac { 33 } { 13 } \right\}

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