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Decide What Values of the Variable Cannot Possibly Be Solutions $\frac { 3 } { x - 9 } + \frac { 7 } { x + 6 } = \frac { 5 } { x ^ { 2 } - 3 x - 54 }$

Question 402

Multiple Choice

Decide what values of the variable cannot possibly be solutions for the equation.
- $\frac { 3 } { x - 9 } + \frac { 7 } { x + 6 } = \frac { 5 } { x ^ { 2 } - 3 x - 54 }$

A) $\left\{ \frac { 65 } { 7 } \right\}$
B) $\{ 5 \}$
C) $\left\{ - \frac { 16 } { 3 } \right\}$
D) $\varnothing$

Decide What Values of the Variable Cannot Possibly Be Solutions 3x−9+7x+6=5x2−3x−54\frac { 3 } { x - 9 } + \frac { 7 } { x + 6 } = \frac { 5 } { x ^ { 2 } - 3 x - 54 }x−93​+x+67​=x2−3x−545​

Multiple Choice

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Decide What Values of the Variable Cannot Possibly Be Solutions $\frac { 3 } { x - 9 } + \frac { 7 } { x + 6 } = \frac { 5 } { x ^ { 2 } - 3 x - 54 }$

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