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Solve the Problem f(x)=5ln⁡2xf ( x ) = 5 \ln 2 x

Question 389

Multiple Choice

Solve the problem.
-Given that f(x) =5ln⁡2xf ( x ) = 5 \ln 2 x , find f−1(x) f ^ { - 1 } ( x ) and give the domain and range of f−1(x) f ^ { - 1 } ( x )


A) f−1(x) =12ex−5\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = \frac { 1 } { 2 } \mathrm { e } ^ { \mathrm { x } - 5 } , domain =(0,∞) = ( 0 , \infty ) , range =(−∞,∞) = ( - \infty , \infty )
B) f−1(x) =12ex/5\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = \frac { 1 } { 2 } \mathrm { e } ^ { \mathrm { x } / 5 } , domain =(−∞,∞) = ( - \infty , \infty ) , range =(0,∞) = ( 0 , \infty )
C) f−1(x) =12ex−5\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = \frac { 1 } { 2 } \mathrm { e } ^ { \mathrm { x } - 5 } , domain =(−∞,∞) = ( - \infty , \infty ) , range =(0,∞) = ( 0 , \infty )
D) f−1(x) =12ex/5\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = \frac { 1 } { 2 } \mathrm { e } ^ { \mathrm { x } / 5 } , domain =(0,∞) = ( 0 , \infty ) , range =(−∞,∞) = ( - \infty , \infty )

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