Solve the Problem $f ( x ) = e ^ { x - 1 } + 3$

Solve the problem.
-Given that $f ( x ) = e ^ { x - 1 } + 3$ , find $f ^ { - 1 } ( x )$ and give the domain and range of $f ^ { - 1 } ( x )$

A) $\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = \ln ( \mathrm { x } - 3 ) + 1$ , domain $= ( 0 , \infty )$ , range $= ( 0 , \infty )$
B) $\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = \ln ( x - 1 ) + 3$ , domain $= ( - \infty , \infty )$ , range $= ( - \infty , \infty )$
C) $\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = \ln ( \mathrm { x } - 1 ) + 3$ , domain $= ( 3 , \infty )$ , range $= ( - \infty , \infty )$
D) $\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = \ln ( x - 3 ) + 1$ , domain $= ( 3 , \infty )$ , range $= ( - \infty , \infty )$

Correct Answer:

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