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Solve for the Indicated Variable A=WB1−(1+z)−s′A = \frac { W B } { 1 - ( 1 + z ) ^ { - s ^ { \prime } } }

Question 408

Multiple Choice

Solve for the indicated variable.
- A=WB1−(1+z) −s′A = \frac { W B } { 1 - ( 1 + z ) ^ { - s ^ { \prime } } } , for s\mathrm { s }


A) s=ln⁡A−ln⁡(A−WB) ln⁡(1+z) s = \frac { \ln A - \ln ( A - W B ) } { \ln ( 1 + z ) }

B) s=ln⁡W(A−AB) (1+z) s = \ln \frac { W } { ( A - A B ) ( 1 + z ) }

C) s=ln⁡Wln⁡[(A−AB) (1−z) ]s = \frac { \ln W } { \ln [ ( A - A B ) ( 1 - z ) ] }

D) s=ln⁡A(A−WB) (1+z) s = \ln \frac { A } { ( A - W B ) ( 1 + z ) }

Correct Answer:

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