Solved

Solve for the Indicated Variable D−D0=(D1−D0)10−kt\mathrm { D } - \mathrm { D } _ { 0 } = \left( \mathrm { D } _ { 1 } - \mathrm { D } _ { 0 } \right) 10 - \mathrm { kt }

Question 235

Multiple Choice

Solve for the indicated variable.
- D−D0=(D1−D0) 10−kt\mathrm { D } - \mathrm { D } _ { 0 } = \left( \mathrm { D } _ { 1 } - \mathrm { D } _ { 0 } \right) 10 - \mathrm { kt } , for t\mathrm { t }


A) t=−1klog⁡D−D0D1−D0t = - \frac { 1 } { k } \log \frac { D - D _ { 0 } } { D _ { 1 } - D _ { 0 } }
B) t=−1klog⁡(D−D1) t = - \frac { 1 } { k } \log \left( D - D _ { 1 } \right)
C) t=−D−D0k(D1−D0) t = - \frac { D - D _ { 0 } } { k \left( D _ { 1 } - D _ { 0 } \right) }
D) t=−1klog⁡DD1t = - \frac { 1 } { k } \log \frac { D } { D _ { 1 } }

Correct Answer:

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