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Use Properties of Logarithms to Evaluate the Expression u=ln⁡a\mathrm { u } = \ln \mathrm { a }

Question 425

Multiple Choice

Use properties of logarithms to evaluate the expression.
-Let u=ln⁡a\mathrm { u } = \ln \mathrm { a } and v=ln⁡b\mathrm { v } = \ln \mathrm { b } . Write the following expression in terms of u\mathrm { u } and v\mathrm { v } without using the funct ln⁡a6b2\ln \frac { a ^ { 6 } } { b ^ { 2 } }


A) 6u+2v6 u + 2 v
B) 6u−2v6 u - 2 v
C) 2u−6v2 u - 6 v
D) u6−v2u ^ { 6 } - v ^ { 2 } n ln.285)

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