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Solve the Equation for Exact Solutions d\mathrm { d } From a Long Wall

Question 226

Multiple Choice

Solve the equation for exact solutions.
-A rotating beacon is located a distance d\mathrm { d } from a long wall. The distance d\mathrm { d } is given by d=2tan⁡2πt\mathrm { d } = 2 \tan 2 \pi \mathrm { t }
where tt is the time measured in seconds since the beacon started rotating. Solve the equation for tt .


A) t=12πarctan⁡d2\mathrm { t } = \frac { 1 } { 2 \pi } \arctan \frac { \mathrm { d } } { 2 }
B) t=2πtan⁡d2\mathrm { t } = 2 \pi \tan \frac { \mathrm { d } } { 2 }
C) t=2πarctan⁡d2\mathrm { t } = 2 \pi \arctan \frac { \mathrm { d } } { 2 }
D) t=12πtan⁡d2\mathrm { t } = \frac { 1 } { 2 \pi } \tan \frac { \mathrm { d } } { 2 }

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