Solve the Equation for Exact Solutions $$\tan ^ { - 1 } ( x + 2 ) + \tan ^ { - 1 } x = \tan ^ { - 1 } \frac { 1 } { 4 }$$

Solve the equation for exact solutions.
- $$\tan ^ { - 1 } ( x + 2 ) + \tan ^ { - 1 } x = \tan ^ { - 1 } \frac { 1 } { 4 }$$

A) $\{ - 5 + 3 \sqrt { 2 } \}$
B) $\left\{ - \frac { 3 } { 4 } , \frac { 3 } { 4 } \right\}$
C) $\{ 2 \}$
D) $\left\{ \frac { 1 } { 2 } \right\}$

Correct Answer:

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