Solve the Equation for Solutions in the Interval [0, 2 $$[ 0,2 \pi )$$

Solve the equation for solutions in the interval [0, 2 $$[ 0,2 \pi )$$
- $$\sin x \cos x = \frac { 1 } { 2 }$$

A) $\left\{ 0 , \frac { \pi } { 4 } , \pi , \frac { 5 \pi } { 4 } \right\}$
B) $\{ 0 \}$
C) $\left\{ \frac { \pi } { 4 } , \frac { 5 \pi } { 4 } \right\}$
D) $\left\{ \frac { \pi } { 12 } , \frac { \pi } { 6 } , \frac { 2 \pi } { 3 } , \frac { 7 \pi } { 12 } , \frac { 7 \pi } { 6 } , \frac { 13 \pi } { 12 } , \frac { 5 \pi } { 3 } \right\}$

Correct Answer:

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Access For Free