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Solve the Equation in the Interval [0∘,360∘)\left[ 0 ^ { \circ } , 360 ^ { \circ } \right)

Question 337

Multiple Choice

Solve the equation in the interval [0∘,360∘) \left[ 0 ^ { \circ } , 360 ^ { \circ } \right) ) . Give solutions to the nearest tenth, if necessary.
- 3sin⁡2θ−sin⁡θ−4=03 \sin ^ { 2 } \theta - \sin \theta - 4 = 0


A) {90∘}\left\{ 90 ^ { \circ } \right\}
B) {180∘}\left\{ 180 ^ { \circ } \right\}
C) {0∘}\left\{ 0 ^ { \circ } \right\}
D) {270∘}\left\{ 270 ^ { \circ } \right\}

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