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Solve the System for X and Y Using Cramer's Rule x+1ay=a1bx+y=b\begin{array} { l } x + \frac { 1 } { a } y = a \\\frac { 1 } { b } x + y = b\end{array}

Question 85

Multiple Choice

Solve the system for x and y using Cramer's rule. Assume a and b are nonzero constants.
- x+1ay=a1bx+y=b\begin{array} { l } x + \frac { 1 } { a } y = a \\\frac { 1 } { b } x + y = b\end{array}


A) {(b(a2−b) ab−1,a(b2−a) ab−1) }\left\{ \left( \frac { b \left( a ^ { 2 } - b \right) } { a b - 1 } , \frac { a \left( b ^ { 2 } - a \right) } { a b - 1 } \right) \right\}

B) {{b(a2−b) a(ab−1) ,a(b2−a) b(ab−1) ) }\left\{ \left\{ \frac { b \left( a ^ { 2 } - b \right) } { a ( a b - 1 ) } , \frac { a \left( b ^ { 2 } - a \right) } { b ( a b - 1 ) } \right) \right\}

C) {((ab−1) (a2−b) a2b,(ab−1) (b2−a) b2a) }\left\{ \left( \frac { ( a b - 1 ) \left( a ^ { 2 } - b \right) } { a ^ { 2 } b } , \frac { ( a b - 1 ) \left( b ^ { 2 } - a \right) } { b ^ { 2 } a } \right) \right\}

D) {(a(a2−b) ab−1,b(b2−a) ab−1) }\left\{ \left( \frac { a \left( a ^ { 2 } - b \right) } { a b - 1 } , \frac { b \left( b ^ { 2 } - a \right) } { a b - 1 } \right) \right\}

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