If the System Has Infinitely Many Solutions, Write the Solution $$\begin{array} { c } x + y - 2 z - 8 = 0 \\3 x + z + 6 = 0 \\2 x - y + 3 z + 14 = 0\end{array}$$

If the system has infinitely many solutions, write the solution set with x arbitrary.
- $$\begin{array} { c } x + y - 2 z - 8 = 0 \\3 x + z + 6 = 0 \\2 x - y + 3 z + 14 = 0\end{array}$$

A) $\{ ( x , - 7 x + 4 , - 3 x - 6 ) \}$
B) $\{ ( x , 7 x + 4 , - 3 x - 6 ) \}$
C) $\{ ( x , - 7 x - 4 , - 3 x - 6 ) \}$
D) $\{ ( x , 7 x - 4 , - 3 x - 6 ) \}$

Correct Answer:

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