Solved

Solve the System by Elimination x+45+2y−x10=3x+54+3y+35=−3\begin{array} { l } \frac { x + 4 } { 5 } + \frac { 2 y - x } { 10 } = 3 \\\frac { x + 5 } { 4 } + \frac { 3 y + 3 } { 5 } = - 3\end{array}

Question 409

Multiple Choice

Solve the system by elimination.
- x+45+2y−x10=3x+54+3y+35=−3\begin{array} { l } \frac { x + 4 } { 5 } + \frac { 2 y - x } { 10 } = 3 \\\frac { x + 5 } { 4 } + \frac { 3 y + 3 } { 5 } = - 3\end{array}


A) {{35,−132) }\left\{ \left\{ 35 , - \frac { 13 } { 2 } \right) \right\}

B) {{−2072,229) }\left\{ \left\{ - \frac { 207 } { 2 } , 229 \right) \right\}

C) {[229,−2072) }\left\{ \left[ 229 , - \frac { 207 } { 2 } \right) \right\}

D) ∅\varnothing

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions