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A Certain Noise Measures 79 Decibels $\mathrm { L } = 10 \log \left( \frac { \mathrm { I } } { \mathrm { I } _ { 0 } } \right)$

Question 196

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A certain noise measures 79 decibels. If the intensity is multiplied by 10, how many decibels will the new noise measure? $\mathrm { L } = 10 \log \left( \frac { \mathrm { I } } { \mathrm { I } _ { 0 } } \right)$

A) 79 decibels
B) 89 decibels
C) 80 decibels
D) 790 decibels

A Certain Noise Measures 79 Decibels L=10log⁡(II0)\mathrm { L } = 10 \log \left( \frac { \mathrm { I } } { \mathrm { I } _ { 0 } } \right)L=10log(I0​I​)

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A Certain Noise Measures 79 Decibels $\mathrm { L } = 10 \log \left( \frac { \mathrm { I } } { \mathrm { I } _ { 0 } } \right)$

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