Solved

Which of the Following Is Correct?
A) sin⁡(−x)=sin⁡x,cos⁡(−x)=cos⁡xtan⁡(−x)=−tan⁡x\begin{array}{l}\sin (-x)=\sin x, \cos (-x)=\cos x \\\tan (-x)=-\tan x\end{array}

Question 42

Multiple Choice

Which of the following is correct?


A) sin⁡(−x) =sin⁡x,cos⁡(−x) =cos⁡xtan⁡(−x) =−tan⁡x\begin{array}{l}\sin (-x) =\sin x, \cos (-x) =\cos x \\\tan (-x) =-\tan x\end{array}
B) sin⁡(−x) =−sin⁡x,cos⁡(−x) =−cos⁡xtan⁡(−x) =tan⁡x\begin{array}{l}\sin (-x) =-\sin x, \cos (-x) =-\cos x \\\tan (-x) =\tan x\end{array}
C) sin⁡(−x) =sin⁡x,cos⁡(−x) =−cos⁡xtan⁡(−x) =−tan⁡x\begin{array}{l}\sin (-x) =\sin x, \cos (-x) =-\cos x \\\tan (-x) =-\tan x\end{array}
D) sin⁡(−x) =−sin⁡x,cos⁡(−x) =cos⁡xtan⁡(−x) =−tan⁡x\begin{array}{l}\sin (-x) =-\sin x, \cos (-x) =\cos x \\\tan (-x) =-\tan x\end{array}
E) sin⁡(−x) =−sin⁡x,cos⁡(−x) =cos⁡xtan⁡(−x) =tan⁡x\begin{array}{l}\sin (-x) =-\sin x, \cos (-x) =\cos x \\\tan (-x) =\tan x\end{array}

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