Fill in the Missing Entries in the Following Partially Completed

Fill in the missing entries in the following partially completed one -way ANOVA table. $$\begin{array} { l | c | c | c | c } \text { Source } & d \boldsymbol { f } & \boldsymbol { S S } & \boldsymbol { M S } = \boldsymbol { S S } / d f & \boldsymbol { F } \text {-statistic } \\\hline \text { Treatment } & 3 & & & 11.16 \\\hline \text { Error } & & 13.72 & 0.686 &\end{array}$$

A) $$\begin{array} { l | c | c | c | c } \text { Source } & \boldsymbol { d f } & \boldsymbol { S S } & \boldsymbol { M S } = \boldsymbol { S S } / d \boldsymbol { f } & \boldsymbol { F } \text {-statistic } \\\hline \text { Treatment } & 3 & 22.97 & 7.66 & 11.16 \\\hline \text { Error } & 20 & 13.72 & 0.686 & \\\hline \text { Total } & 23 & 36.69 & &\end{array}$$
B) $$\begin{array} { l | c | c | c | c } \text { Source } & d \boldsymbol { f } & \boldsymbol { S S } & \boldsymbol { M S } = \boldsymbol { S S } / d f & \boldsymbol { F } \text {-statistic } \\\hline \text { Treatment } & 3 & 2.55 & 7.66 & 11.16 \\\hline \text { Error } & 20 & 13.72 & 0.686 & \\\hline \text { Total } & 23 & 16.27 & &\end{array}$$
C) $$\begin{array} { l | c | c | c | c } \text { Source } & d f & \boldsymbol { S S } & \boldsymbol { M S } = \boldsymbol { S S } / d \boldsymbol { d } & \boldsymbol { F } \text {-statistic } \\\hline \text { Treatment } & 3 & 48.80 & 16.27 & 11.16 \\\hline \text { Error } & 20 & 13.72 & 0.686 & \\\hline \text { Total } & 23 & 62.52 & &\end{array}$$
D) $$\begin{array} { l | c | c | c | c } \text { Source } & \boldsymbol { d f } & \boldsymbol { S S } & \boldsymbol { M S } = \boldsymbol { S S } / \boldsymbol { d f } & \boldsymbol { F } \text {-statistic } \\\hline \text { Treatment } & 3 & 0.184 & 0.061 & 11.16 \\\hline \text { Error } & 20 & 13.72 & 0.686 & \\\hline \text { Total } & 23 & 13.90 & &\end{array}$$

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