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If P(A) = 0 $\cap$ \ B) =080, Then P(A $\cup$ B) Is

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If P(A) = 0.65, P(B) =0.76 and P(A $\cap$ \ B) =0.80, then P(A $\cup$ B) is: $\begin{array} { | l | l | } \hline \text { A. } & 0.65 . \\\hline \text { B. } & 0.61 . \\\hline \text { C. } & 0.80 . \\\hline \text { D. } & 0.02 . \\\hline\end{array}$

If P(A) = 0 ∩\cap∩ \ B) =080, Then P(A ∪\cup∪ B) Is

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If P(A) = 0 $\cap$ \ B) =080, Then P(A $\cup$ B) Is

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