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Evaluate the Integral ∫e−0.05x1−e−0.05x dx\int \frac { e ^ { - 0.05 x } } { 1 - e ^ { - 0.05 x } } \mathrm {~d} x

Question 62

Multiple Choice

Evaluate the integral.
∫e−0.05x1−e−0.05x dx\int \frac { e ^ { - 0.05 x } } { 1 - e ^ { - 0.05 x } } \mathrm {~d} x


A) ln⁡∣1−e−0.05x∣20−x+C\frac { \ln \left| 1 - e ^ { - 0.05 x } \right| } { 20 } - x + C
B) −20ln⁡∣1−e−0.05x∣+x+C- 20 \ln \left| 1 - e ^ { - 0.05 x } \right| + x + C
C) 20ln⁡∣1−e−0.05x∣−x+C20 \ln \left| 1 - e ^ { - 0.05 x } \right| - x + C
D) 0.05ln⁡∣1−e−0.05x∣+x+C0.05 \ln \left| 1 - e ^ { - 0.05 x } \right| + x + C
E) −0.05ln⁡∣1−e−0.05x∣−x+C- 0.05 \ln \left| 1 - e ^ { - 0.05 x } \right| - x + C

Correct Answer:

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