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Calculate the Values Of ∂f∂x\frac { \partial f } { \partial x }

Question 134

Multiple Choice

Calculate the values of ∂f∂x\frac { \partial f } { \partial x } , ∂f∂y\frac { \partial f } { \partial y } , and ∂f∂z\frac { \partial f } { \partial z } at (4,1,2) ( 4,1,2 ) . f(x,y,z) =320z7+y0.6f ( x , y , z ) = \frac { 320 z } { 7 + y ^ { 0.6 } }


A) ∂f∂x∣(4,1,2) =6\left. \frac { \partial f } { \partial x } \right| _ { ( 4,1,2 ) } = 6 , ∂f∂y∣(4,1,2) =0\left. \frac { \partial f } { \partial y } \right| _ { ( 4,1,2 ) } = 0 , ∂f∂y∣(4,1,2) =0\left. \frac { \partial f } { \partial y } \right| _ { ( 4,1,2 ) } = 0
B) ∂f∂x∣(4,1,2) =0\left. \frac { \partial f } { \partial x } \right| _ { ( 4,1,2 ) } = 0 , ∂f∂y∣(4,1,2) =−6\left. \frac { \partial f } { \partial y } \right| _ { ( 4,1,2 ) } = - 6 , ∂f∂y∣(4,1,2) =40\left. \frac { \partial f } { \partial y } \right| _ { ( 4,1,2 ) } = 40
C) ∂f∂x∣(4,1,2) =−40\left. \frac { \partial f } { \partial x } \right| _ { ( 4,1,2 ) } = - 40 , ∂f∂y∣(4,1,2) =6\left. \frac { \partial f } { \partial y } \right| _ { ( 4,1,2 ) } = 6 , ∂f∂y∣(4,1,2) =0\left. \frac { \partial f } { \partial y } \right| _ { ( 4,1,2 ) } = 0
D) ∂f∂x∣(4,1,2) =0\left. \frac { \partial f } { \partial x } \right| _ { ( 4,1,2 ) } = 0 , ∂f∂y∣(4,1,2) =40\left. \frac { \partial f } { \partial y } \right| _ { ( 4,1,2 ) } = 40 , ∂f∂y∣(4,1,2) =6\left. \frac { \partial f } { \partial y } \right| _ { ( 4,1,2 ) } = 6
E) ∂f∂x∣(4,1,2) =0\left. \frac { \partial f } { \partial x } \right| _ { ( 4,1,2 ) } = 0 , ∂f∂y∣(4,1,2) =−6\left. \frac { \partial f } { \partial y } \right| _ { ( 4,1,2 ) } = - 6 , ∂f∂y∣(4,1,2) =320\left. \frac { \partial f } { \partial y } \right| _ { ( 4,1,2 ) } = 320

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