Solved

Find the Derivative of the Function w(x)=2sec⁡(x)⋅tan⁡(x2−2)w ( x ) = 2 \sec ( x ) \cdot \tan \left( x ^ { 2 } - 2 \right)

Question 18

Multiple Choice

Find the derivative of the function. w(x) =2sec⁡(x) ⋅tan⁡(x2−2) w ( x ) = 2 \sec ( x ) \cdot \tan \left( x ^ { 2 } - 2 \right)


A) w′(x) =2sec⁡2x⋅sin⁡x⋅tan⁡(x2−2) +4x⋅sec⁡x⋅sec⁡2(x2−2) w ^ { \prime } ( x ) = 2 \sec ^ { 2 } x \cdot \sin x \cdot \tan \left( x ^ { 2 } - 2 \right) + 4 x \cdot \sec x \cdot \sec ^ { 2 } \left( x ^ { 2 } - 2 \right)
B) w′(x) =2sec⁡2x⋅sin⁡x⋅tan⁡(x2−2) +4x⋅sec⁡x⋅sec⁡2(2x−2) w ^ { \prime } ( x ) = 2 \sec ^ { 2 } x \cdot \sin x \cdot \tan \left( x ^ { 2 } - 2 \right) + 4 x \cdot \sec x \cdot \sec ^ { 2 } ( 2 x - 2 )
C) w′(x) =2sec⁡2x⋅sin⁡x⋅tan⁡(x2+2) +4x⋅sec⁡x⋅sec⁡2(2x−2) w ^ { \prime } ( x ) = 2 \sec ^ { 2 } x \cdot \sin x \cdot \tan \left( x ^ { 2 } + 2 \right) + 4 x \cdot \sec x \cdot \sec ^ { 2 } ( 2 x - 2 )
D) w′(x) =2sec⁡2x⋅sin⁡x⋅tan⁡(x2−2) w ^ { \prime } ( x ) = 2 \sec ^ { 2 } x \cdot \sin x \cdot \tan \left( x ^ { 2 } - 2 \right)
E) w′(x) =2sec⁡2x⋅sin⁡x⋅tan⁡(x2−2) +4x⋅sec⁡x⋅sec⁡2(x2−4) w ^ { \prime } ( x ) = 2 \sec ^ { 2 } x \cdot \sin x \cdot \tan \left( x ^ { 2 } - 2 \right) + 4 x \cdot \sec x \cdot \sec ^ { 2 } \left( x ^ { 2 } - 4 \right)

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions