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Find the Derivative of the Function u(x)=sec⁡(x5.2+2.8x−9)u ( x ) = \sec \left( x ^ { 5.2 } + 2.8 x - 9 \right)

Question 50

Multiple Choice

Find the derivative of the function. u(x) =sec⁡(x5.2+2.8x−9) u ( x ) = \sec \left( x ^ { 5.2 } + 2.8 x - 9 \right)


A) u′(x) =(5.2x4.2+2.8) sec⁡(x5.2−2.8x−9) tan⁡(x5.2−2.8x−9) u ^ { \prime } ( x ) = \left( 5.2 x ^ { 4.2 } + 2.8 \right) \sec \left( x ^ { 5.2 } - 2.8 x - 9 \right) \tan \left( x ^ { 5.2 } - 2.8 x - 9 \right)
B) u′(x) =(5.2x4.2−2.8) sec⁡(x5.2+2.8x−9) tan⁡(x5.2+2.8x−9) u ^ { \prime } ( x ) = \left( 5.2 x ^ { 4.2 } - 2.8 \right) \sec \left( x ^ { 5.2 } + 2.8 x - 9 \right) \tan \left( x ^ { 5.2 } + 2.8 x - 9 \right)
C) u′(x) =(5.2x4.2−2.8) sec⁡(x5.2−2.8x−9) tan⁡(x5.2+2.8x−9) u ^ { \prime } ( x ) = \left( 5.2 x ^ { 4.2 } - 2.8 \right) \sec \left( x ^ { 5.2 } - 2.8 x - 9 \right) \tan \left( x ^ { 5.2 } + 2.8 x - 9 \right)
D) u′(x) =(5.2x4.2+2.8) sec⁡(x5.2+2.8x−9) tan⁡(x5.2+2.8x−9) u ^ { \prime } ( x ) = \left( 5.2 x ^ { 4.2 } + 2.8 \right) \sec \left( x ^ { 5.2 } + 2.8 x - 9 \right) \tan \left( x ^ { 5.2 } + 2.8 x - 9 \right)
E) u′(x) =(5.2x4.2−2.8) sec⁡(x5.2−2.8x−9) tan⁡(x5.2−2.8x−9) u ^ { \prime } ( x ) = \left( 5.2 x ^ { 4.2 } - 2.8 \right) \sec \left( x ^ { 5.2 } - 2.8 x - 9 \right) \tan \left( x ^ { 5.2 } - 2.8 x - 9 \right)

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