Solved

Find the Derivative of the Function g(x)=9sin⁡(x)⋅tan⁡xg ( x ) = 9 \sin ( x ) \cdot \tan x

Question 62

Multiple Choice

Find the derivative of the function. g(x) =9sin⁡(x) ⋅tan⁡xg ( x ) = 9 \sin ( x ) \cdot \tan x


A) g′(x) =9cos⁡(x) ⋅tan⁡x+9sin⁡(x) ⋅csc⁡2xg' ( x ) = 9 \cos ( x ) \cdot \tan x + 9 \sin ( x ) \cdot \csc ^ { 2 } x
B) g′(x) =9cos⁡(x) ⋅tan⁡x+9sin⁡(x) ⋅sec⁡2xg '( x ) = 9 \cos ( x ) \cdot \tan x + 9 \sin ( x ) \cdot \sec ^ { 2 } x
C) g′(x) =9cos⁡(x) ⋅tan⁡x−9sin⁡(x) ⋅cot⁡xg '( x ) = 9 \cos ( x ) \cdot \tan x - 9 \sin ( x ) \cdot \cot x
D) g′(x) =9cos⁡(x) ⋅tan⁡x+9cos⁡(x) ⋅cot⁡xg' ( x ) = 9 \cos ( x ) \cdot \tan x + 9 \cos ( x ) \cdot \cot x
E) g′(x) =9cos⁡(x) ⋅tan⁡x−9sin⁡(x) ⋅sec⁡2xg '( x ) = 9 \cos ( x ) \cdot \tan x - 9 \sin ( x ) \cdot \sec ^ { 2 } x

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions