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Let A=[012−23−1213]A = \left[ \begin{array} { c c c } 0 & \frac { 1 } { 2 } & - \frac { 2 } { 3 } \\- 1 & 2 & \frac { 1 } { 3 }\end{array} \right]

Question 84

Multiple Choice

Let A=[012−23−1213]A = \left[ \begin{array} { c c c } 0 & \frac { 1 } { 2 } & - \frac { 2 } { 3 } \\- 1 & 2 & \frac { 1 } { 3 }\end{array} \right] and B=[−260212−1]B = \left[ \begin{array} { c c c } - 2 & 6 & 0 \\2 & \frac { 1 } { 2 } & - 1\end{array} \right] . Evaluate 3A−4B3 A - 4 B .


A) [8−2212−2−1145]\left[ \begin{array} { c c c } 8 & - 22 \frac { 1 } { 2 } & - 2 \\- 11 & 4 & 5\end{array} \right]
B) [−82212211−4−5]\left[ \begin{array} { c c c } - 8 & 22 \frac { 1 } { 2 } & 2 \\11 & - 4 & - 5\end{array} \right]
C) [−82512−258−3]\left[ \begin{array} { c c c } - 8 & 25 \frac { 1 } { 2 } & - 2 \\5 & 8 & - 3\end{array} \right]
D) [8−25122−5−83]\left[ \begin{array} { c c c } 8 & - 25 \frac { 1 } { 2 } & 2 \\- 5 & - 8 & 3\end{array} \right]
E) [8−2212−2−11−45]\left[ \begin{array} { c c c } 8 & - 22 \frac { 1 } { 2 } & - 2 \\- 11 & - 4 & 5\end{array} \right]

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