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Maximize
​ p=12x+10yp = 12 x + 10 y ​
Subject to
​

Question 117

Essay

Maximize
​ p=12x+10yp = 12 x + 10 y ​
subject to
​ x+y≤40x≥3−x+2y≥0x≥0,y≥0\begin{aligned}x + y & \leq 40 \\x & \geq 3 \\- x + 2 y & \geq 0 \\x \geq 0 , y & \geq 0\end{aligned} ​
Please enter your answer as three numbers, separated by commas in the order p, x, y. If there is no solution, enter no solution.

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