Use the given transition matrix P and the given initial distribution vector v to obtain the two-step transition matrix and the distribution vector after two steps.

P = \left[ \begin{array} { c c } 0.9 & 0.1 \\0 & 1\end{array} \right]

v = \left[ \begin{array} { l l } 0.9 & 0.1\end{array} \right]

A)The two-step transition matrix is

\left[ \begin{array} { c c } 0.81 & 0.19 \\0 & 1\end{array} \right]

The distribution vector is

\left[ \begin{array} { l l } 1 & 0\end{array} \right]

B) The two-step transition matrix is

\left[ \begin{array} { c c } 0 & 1 \\0.81 & 0.19\end{array} \right]

The distribution vector is

\left[ \begin{array} { l l } 0 & 1\end{array} \right]

C) The two-step transition matrix is

\left[ \begin{array} { c c } 0.81 & 0.01 \\0 & 1\end{array} \right]

The distribution vector is

\left[ \begin{array} { l l } 0.729 & 0.271\end{array} \right]

D) The two-step transition matrix is

\left[ \begin{array} { c c } 0.81 & 0.19 \\0 & 1\end{array} \right]

The distribution vector is

\left[ \begin{array} { l l } 0.81 & 0\end{array} \right]

E) The two-step transition matrix is

\left[ \begin{array} { c c } 0.81 & 0.19 \\0 & 1\end{array} \right]

The distribution vector is

\left[ \begin{array} { l l } 0.729 & 0.271\end{array} \right]

A Bag Contains 4 Red Marbles, 2 Green Ones, 2 29\frac { 2 } { 9 }92​

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A Bag Contains 4 Red Marbles, 2 Green Ones, 2 $\frac { 2 } { 9 }$

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