Solved

Students a Growing School District Tracks the Student Population Growth  students =119.53+172.03 year  Sample size: 6 R-sq =0.987 \begin{array}{l}\text { students }=119.53+172.03 \text { year } \\ \text { Sample size: } 6 \\ \text { R-sq }=0.987\end{array}

Question 43

Essay

Students A growing school district tracks the student population growth over the years from 2008 to 2013. Here are the regression results and a residual plot.
 students =119.53+172.03 year  Sample size: 6 R-sq =0.987 \begin{array}{l}\text { students }=119.53+172.03 \text { year } \\ \text { Sample size: } 6 \\ \text { R-sq }=0.987\end{array}

 Students A growing school district tracks the student population growth over the years from 2008 to 2013. Here are the regression results and a residual plot.    \begin{array}{l}\text { students }=119.53+172.03 \text { year } \\ \text { Sample size: } 6 \\ \text { R-sq }=0.987\end{array}       a. Explain why despite a high R-sq, this regression is not a successful model. To linearize the data, the log (base 10) was taken of the student population. Here are the results. Dependent Variable:   \log   (students) Sample size: 6  R-s q=0.994     \begin{array}{lrr}\text { Parameter } & \text { Estimate } & \text { Std. Err. } \\ \text { constant } & 2.871 & 0.0162 \\ \text { year } & 0.0389 & 0.00152\end{array}       b. Describe the success of the linearization. c. Interpret R-sq in the context of this problem. d. Predict the student population in 2014.

a. Explain why despite a high R-sq, this regression is not a successful model.
To linearize the data, the log (base 10) was taken of the student population. Here are the
results. Dependent Variable: log⁡ \log (students)
Sample size: 6
R−sq=0.994R-s q=0.994

 Parameter  Estimate  Std. Err.  constant 2.8710.0162 year 0.03890.00152 \begin{array}{lrr}\text { Parameter } & \text { Estimate } & \text { Std. Err. } \\ \text { constant } & 2.871 & 0.0162 \\ \text { year } & 0.0389 & 0.00152\end{array}

 Students A growing school district tracks the student population growth over the years from 2008 to 2013. Here are the regression results and a residual plot.    \begin{array}{l}\text { students }=119.53+172.03 \text { year } \\ \text { Sample size: } 6 \\ \text { R-sq }=0.987\end{array}       a. Explain why despite a high R-sq, this regression is not a successful model. To linearize the data, the log (base 10) was taken of the student population. Here are the results. Dependent Variable:   \log   (students) Sample size: 6  R-s q=0.994     \begin{array}{lrr}\text { Parameter } & \text { Estimate } & \text { Std. Err. } \\ \text { constant } & 2.871 & 0.0162 \\ \text { year } & 0.0389 & 0.00152\end{array}       b. Describe the success of the linearization. c. Interpret R-sq in the context of this problem. d. Predict the student population in 2014.

b. Describe the success of the linearization.
c. Interpret R-sq in the context of this problem. d. Predict the student population in 2014.

Correct Answer:

verifed

Verified

a. Even though R-sq = 98.7%, the residua...

View Answer

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions