Solved

The Second-Order Decomposition of NO2 Has a Rate Constant of 0.255

Question 36

Multiple Choice

The second-order decomposition of NO2 has a rate constant of 0.255 L mol-1 s-1. How much NO2 decomposes in 4.00 s if the initial concentration of NO2 (1.00 L volume) is 1.33 mol L-1?


A) 1.8 mol
B) 0.85 mol
C) 0.48 mol
D) 0.77 mol
E) 0.56 mol

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions